Jan 7, 2021 · Apparent weight is zero, because the downward force due to gravity is equal to the upward force of buoyancy, and these two cancel out. IF one defines apparent density as …

Oct 11, 2020 · According to this source, there are $5077$ visible stars in the night sky, and a full sky area of $41253$ square degrees of sky. This makes for a density of $0.12$ stars per …

Since, historically, Vega has been used as the reference zero-point (having an apparent magnitude around 0.03), I tried doing a simple calculation to find out the apparent magnitude …

Mar 24, 2016 · Relative density of a solid is the ratio of density of solid to that of water: $$\rho_r=\frac{\rho_{solid}}{\rho_{water}}$$ Now, according to Archimedes' principle, the …

Gold itself has a density of 19.3, silver as 10.5. Here we would expect of a silver-gold alloy, that the 8.8 extra by gold appears in the 0.8 extra over of silver. This means that putting 10 parts of …

Aug 28, 2018 · Use density = mass/volume. The most important thing here is finding the volume of the object, which is mass of the object divided by density of the object. I think you can find …

Jul 25, 2017 · Let's say we know the "real" flux of a star in a certain bandwidth because we consider it a black body of known temperature. That's just the integer of the power density, so …

Nov 16, 2015 · With this equation we can see immediately that a black hole with the same mass as the Sun would have the (enormously high) density of $1.85 \times 10^{19}$ kg/m$^3$. …

Sep 13, 2022 · Consequently the received power density drops by $1-Hr/c$ from that factor alone. Combined with the inverse square law, this would suggest the apparent brightness dropping …

Apr 7, 2016 · If the density of the fluid is equal to the density of the object then to balance the weight of the object and the upthrust the object has to be totally immersed. Push the object …